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(C) Given the ratio of amplitudes $A_1 : A_2 = 2 : 3$.Since intensity $I \propto A^2$,the ratio of intensities is $\frac{I_1}{I_2} = \left(\frac{A_1}{

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$1 : 25$

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(C) Given the ratio of amplitudes $A_1 : A_2 = 2 : 3$.Since intensity $I \propto A^2$,the ratio of intensities is $\frac{I_1}{I_2} = \left(\frac{A_1}{A_2}\right)^2 = \left(\frac{2}{3}\right)^2 = \frac{4}{9}$.Let $I_1 = 4k$ and $I_2 = 9k$.The intensity of the minimum is $I_{\min} = (\sqrt{I_1} - \sqrt{I_2})^2 = (\sqrt{4k} - \sqrt{9k})^2 = (2\sqrt{k} - 3\sqrt{k})^2 = (-\sqrt{k})^2 = k$.The intensity of the maximum is $I_{\max} = (\sqrt{I_1} + \sqrt{I_2})^2 = (\sqrt{4k} + \sqrt{9k})^2 = (2\sqrt{k} + 3\sqrt{k})^2 = (5\sqrt{k})^2 = 25k$.Therefore,the ratio $\frac{I_{\min}}{I_{\max}} = \frac{k}{25k} = \frac{1}{25}$.

The amplitude of the light waves emerging from the two slits in Young's experiment is in the ratio of $2 : 3$. The ratio of the intensity of the minimum to that of the consecutive maximum will be:

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